dbspl Posted December 15, 2013 at 01:44 PM Report Share Posted December 15, 2013 at 01:44 PM Does anyone know how the major hash-marks are calibrated on the "engage display" for the engine and electric motor power bands? If I had to guess, I would say 10 kw, but after I thought about it, that seems a little low. Any ideas? Quote Link to comment Share on other sites More sharing options...
larryh Posted December 15, 2013 at 01:50 PM Report Share Posted December 15, 2013 at 01:50 PM (edited) For the empower screen, each mark represents 10 kW. I'm not sure for the other displays. The approximate power required for various speeds is shown below: mph kW20 2.730 4.640 7.150 10.860 15.370 22.6 Edited December 15, 2013 at 01:50 PM by larryh Quote Link to comment Share on other sites More sharing options...
dbspl Posted December 16, 2013 at 11:51 PM Author Report Share Posted December 16, 2013 at 11:51 PM Got it. Thanks. I thought that was it, but I also noticed the display range isn't enough to represent the engine (or motor) power when under high/max loads. But I guess if you're driving the car that hard you don't need to be looking at the display anyway:) Quote Link to comment Share on other sites More sharing options...
larryh Posted December 16, 2013 at 11:57 PM Report Share Posted December 16, 2013 at 11:57 PM (edited) When switching between Engage and Empower, the marks don't seem to line up. The marks seem to represent about 12 on the Engage screen--but I can't be sure. When power is as 20 kW, two marks, on the Empower Screen, the bar occupies less than two marks on the Engage screen. If you accelerate hard, it could be that the car rescales the display. I haven't tried it. Edited December 16, 2013 at 11:59 PM by larryh Quote Link to comment Share on other sites More sharing options...
meyersnole Posted December 17, 2013 at 06:15 AM Report Share Posted December 17, 2013 at 06:15 AM (edited) For the empower screen, each mark represents 10 kW. I'm not sure for the other displays. The approximate power required for various speeds is shown below: mph kW20 2.730 4.640 7.150 10.860 15.370 22.6 Larry, how would I read that second column? Is that the amount of energy consumed in an hour at that speed? So I could look at it this way? MPH kW 20 miles Time Hours:mins20 2.7 2.70 1 1:0030 4.6 3.07 0.67 0:4040 7.1 3.55 0.50 0:3050 10.8 4.32 0.40 0:2460 15.3 5.10 0.33 0:2070 22.6 6.46 0.29 0:17 If that is correct, I must be doing something wrong. The above 20 mile chart suggests that you might be able to travel 20 miles at 70 mph, where I am almost sure that the range would be no where near that... what am I doing wrong? In the chart, it takes 17 mins or .29 hours to go 20 miles consuming 6.46 kW, right? Edited December 17, 2013 at 06:23 AM by meyersnole Quote Link to comment Share on other sites More sharing options...
larryh Posted December 17, 2013 at 09:33 AM Report Share Posted December 17, 2013 at 09:33 AM (edited) The second column is the rate at which energy is consumed. So yes, if you were able to consume 22.6 kW of power for 1 hour, you would use 22.6 kWh of energy. As you have shown, going 70 mph for 20 miles would take 20/70 = 0.286 hours, or 0.286*22.6 = 6.46 kWh of energy. However, you can only extract about 5.8 kWh of energy from the HVB before entering hybrid mode. You might be able to go at most 5.8 kWh / 22.6 kW = 0.257 hours or 15.4 minutes at 70 mph, or about 18 miles. It depends on how much energy you can extract from the battery. The 5.8 kWh is what I have observed for going about 30 mph. If you go faster, the ICE will turn on earlier, so you won't be able to extract that much. If you look at the Empower display when it turns to hybrid mode, the threshold for turning on the ICE is about 20 kW. At 30 mph you will be below the threshold and be able to extract more energy (up to about 5.8 or 5.9 kWh). At 70 mph, you will be over the threshold and will not be able to continue to extract more energy from the battery. You can easily compute the power consumed at constant speed from the MPGe for that speed as shown on the car's display using a trip odometer. MPGe is miles / equivalent gallon. An equivalent gallon is 33.705 kWh of energy. So at 70 mph, MPGe is about 104 MPGe. That amounts to 1 / 104 = 0.00962 equivalent gallons / mile = 0.00962*33.705 = 0.324 kWh / mile. You will go 70 miles in one hour, so you will have then consumed 0.324 * 70 = 22.6 kWh of energy. The power required to go 70 mph is thus 22.6 kW. Edited December 17, 2013 at 09:52 AM by larryh Quote Link to comment Share on other sites More sharing options...
meyersnole Posted December 17, 2013 at 11:52 PM Report Share Posted December 17, 2013 at 11:52 PM Thanks Larry, so it is good to know the math was right I just had the numbers in my head wrong. I was comparing against the total battery ~7.1 kW and that just did not make sense. That table was very helpful, I know that the section of my commute where I am going 55-60 is killing my range, now I can see by how much ;) Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.